Answers

2015-02-24T18:25:05+05:30
SOLN;
At first taken,
2A=3B
=>A=3B/2.
Then, taken 4B=5C.
=>C=4B/5
So A:C,
3B/2;4B/5,
THE FINAL ANS IS,
A;C=3/2;4/5
1 5 1
given that,
GIVEN THAT, 2A=3B AND 4B=5C. MULTIPLY BOTH LHS AND RHS OF 2A=3B WITH 4 AND 4B=5C WITH 3. AFTER MULTIPLYING WE GET 8A=12B AND 12B=15C. => 8A=15C => A:C=15:8