I have attached the figure along with it the figure is a little bit clumsy!!!!!!

In ▲ABC , X and Y are the midpoints of sides AC and AB

XY||CB and XY||PQ (Mid Point Theorem)

▲XYB and ▲XYC are on the same base XY and between same parallels XY and CB

Therefore,ar(XYB)=ar(XYC)....................equation 1

__If it is given that A is the mid point of PQ then only we can prove the rest __

__then XY=PA AND XY=AQ__

in quadrilateral PAYX and AQYX

since one pair of opposit sides are equal and parallel these two are parallelograms

Parallelograms PAYX AND AQYX are on the same base XY and between same parallels XY and PQ

therefore ar(PAYX)=ar(AQYX).............equation 2

equation 1 +equation 2

ar(ABP)=ar(ACQ)

Hence Proved