# A metal cube of volume 2933 cu.cm is melted and three smaller cubes are made out of it. If the edges of two smaller cubes are 5 cm and 4 cm, find the edge of the third smaller cube

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by charlotteds9

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by charlotteds9

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Volume of bigger metal cube=2933cu.cm

volume of 1st smaller cube = 5^3 = 125 cu.cm

volume of 2nd smaller cube = 4^3 = 64 cu.cm

therefore,

volume of 3rd smaller cube = 2933-(125+64)

= 2933 - 189

= 2744

=> volume of 3rd small cube = a^3 = 2744

so,

edge of the 3rd small cube = cube root of 2744 i.e. = 14

this implies that edge of the 3rd cube = 14cm

volume of 1st smaller cube = 5^3 = 125 cu.cm

volume of 2nd smaller cube = 4^3 = 64 cu.cm

therefore,

volume of 3rd smaller cube = 2933-(125+64)

= 2933 - 189

= 2744

=> volume of 3rd small cube = a^3 = 2744

so,

edge of the 3rd small cube = cube root of 2744 i.e. = 14

this implies that edge of the 3rd cube = 14cm