# A cylindrical vessel open at the top has a base of radius 10.5cm and height 14cm find the cost of painting the inner part of the vessel at the rate of ₹10 per sq.cm take22/7 as

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by Pha

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by Pha

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R = 10.5 cm

h = 14 cm

inner area = inner curved surface area + base area

= 2πrh + πr²

= 2×(22/7)×14×10.5 + (22/7)×10.5²

= 1270.5 cm²

rate = ₹10 per cm²

cost = 1270.5×10 = ₹12705

h = 14 cm

inner area = inner curved surface area + base area

= 2πrh + πr²

= 2×(22/7)×14×10.5 + (22/7)×10.5²

= 1270.5 cm²

rate = ₹10 per cm²

cost = 1270.5×10 = ₹12705

h=14 cm

inner area=base area+inner curved area

base area=πr²=22/7*10.5²=346.5 cm²

Inner curved area=2πrh=2*22/7*10.5*14=924 cm²

then inner curved area=346.5+924=1270.5 cm²

10 ruppee per cm²\

so total cost=10*1270.5=12705 ruppee