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2015-03-01T02:45:00+05:30

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Angle DAB + angle DCB = 180      (sum of opposite sides of a cyclic quadrilateral)
angleDCB +50 =180
angle DCB =130
.'. angle y= 130

'.' OA=OB                                    (radius of circle)
angle OAB = angle OBA = 50        (angles opposite to equal sides are equal)
angle OAB + angle OBA = angle BOD      (exterior angle property of triangle)
50 +50 =angle x
100 =angle x
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2015-03-01T15:12:13+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
X = 100°

since  the angle subtended by the common chord on the center is twice the angle subtended by any other point on the circle to that chord.

ABO is isosceles since 
  OA=OB= RADIUS OF THE CIRCLE.

so angle ABO = 50 .

so AOB = 80. x = 180 - AOB = 180 - 80 = 100

and is cyclic quadrilateral the opposite angles are supplementary

so y = 180 - 50 = 130°
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