# The half life period of a radioactive isotope is 2hours. After 6hours what fraction of the initial quantity of the isotope will be left behind?

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by horlermine

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by horlermine

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Now the half life of the isotope is given 2 hours. After 6 hours the no of half lives will be 3.

So the The amount of radioactive isotope remaining can be calculated as:

Nt = No x 1/2^n where, Nt is the amount of radio isotope remaining. No is the original amount of radio isotope.

N is the no of half lives.

Now let the original amount of isotope is one, then by using the formula we can calculate the remaining of isotope as:

Nt = 1x1/2^3

= 1x1/8

= 1/8

So the The amount of radioactive isotope remaining can be calculated as:

Nt = No x 1/2^n where, Nt is the amount of radio isotope remaining. No is the original amount of radio isotope.

N is the no of half lives.

Now let the original amount of isotope is one, then by using the formula we can calculate the remaining of isotope as:

Nt = 1x1/2^3

= 1x1/8

= 1/8

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

If initial quantity of a radioactive isotope is N₀, after n complete half lives, the quantity remaining will be .

Half life = 2 hours

time = 6 hours

number of half lives = 6/2 = 3

So quantity of isotope left behind =

So only of the initial quantity will remain after 6 hours.

Half life = 2 hours

time = 6 hours

number of half lives = 6/2 = 3

So quantity of isotope left behind =

So only of the initial quantity will remain after 6 hours.