Answers

2014-04-19T18:04:11+05:30
Dimensions of time period = t
0
2014-04-19T18:30:07+05:30
The density has dimension ML^{-3}
so take that as D 
the acceleration has dimension LT^{-2}
take it as A
the force has dimension MLT^{-2}
Take it as F
so time period has dimension as D^{ -\frac{1}{6} }A^{ -\frac{2}{3} }F^{ \frac{1}{6} }
actual dimension is T for time
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