# A ball dropped from a height of 10m loses of its energy after impact on ground. how much height will it gain after one impact

1
by jannath

loses ____ of its energy??

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by jannath

loses ____ of its energy??

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Let us say the ball loses half of its energy after impact on the ground. The loss happens due to inelastic collision.

Initial Potential Energy of the ball = m g h

Total energy in the ball = KE + PE = m g h

Suppose it loses 1/n th part of its energy. then 1 - 1/n is the remaining energy.

Total energy after impact = m g h (n-1)/n

It will rise to a height of h*(n-1)/n

suppose n = 2, that is the ball loses half of its energy on impact. Then,

the height will be = h/2

Initial Potential Energy of the ball = m g h

Total energy in the ball = KE + PE = m g h

Suppose it loses 1/n th part of its energy. then 1 - 1/n is the remaining energy.

Total energy after impact = m g h (n-1)/n

It will rise to a height of h*(n-1)/n

suppose n = 2, that is the ball loses half of its energy on impact. Then,

the height will be = h/2