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2015-03-02T20:34:30+05:30

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Data set A: 4, 6, 7, 1, 9,
   mean μ = 5.4        variance = σ² =  [1.4²+0.6²+1.6²+4.4²+3.6²]/5 = 7.44
   σ = 2.7276
         coefficient of variation = CV = σ/μ = 0.505

dataset B :  6, 3, 5, 8, 10
 mean= 6.4        variance = σ² = [0.4²+3.4²+1.4²+1.6²+3.6²]/5 = 5.84
   σ = 2.4166
       coefficient of variation = σ/μ=  0.3776

The data set A is more dispersed.   Its spreads wider more than data set B.

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