Log in to add a comment

## Answers

AB=CD......1

BC=AD......2

It is observed that,

DR=DS (tangent on the circle from point D).....3

CR=CQ (tangent on the circle from point C).....4

BP=BQ (tangent on the circle from point B).....5

AP=AS (tangent on the circle from point A)....6

Adding equation 3, 4, 5 & 6

we get,

DR+CR+BP+AP=DS+CQ+BQ+AS

CD+AB=AD+BC......7

On putting values of equation 1, 2 and 7

we get,

2AB=2BC

Compairing equation 1, 2 and 7

we get,

AB=BC=CD=AD

Hence, ABCD is a rhombus