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*by using the formula s = a+(n-1)d*

*where s is the last term, a is the 1st term, d is the common difference*

*the first and last terms that are divisible by 3 between 100 to 200 without including 100 and 200 are 102 (34 times) and 198 (66 times)*

*and the common difference is 3 since they are the multiples of 3*

*so, a=102, s=198, d=3*

*by substituiting them in formula we get*

*198=102+(n-1)3*

*n-1=198-102/3*

*n-1=96/3*

*n-1=32*

*n=32+1*

*n=33*

*so the number of terms that are divisible by 3 is 33 terms*

*Sn = n/2(a+l)*

*S49 = 33/2 (102+198)*

*= 33/2×300*

*= 33×150*

*= 4950*

*there fore the sum of the 33 terms is 4950*
The Brainliest Answer!

102, 105. 108,........... 198

An = A + (n-1) d

198 = 102 + (n-1) 3

96= 3n-3

99= 3n

n = 33

Sn = n/2 (a+l)

S₃₃ = 33/2 (102+198)

S₃₃ = 33/2 ( 300) = 4950