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orbital\ velocity\ \alpha  \frac{1}{ \sqrt{R} }

Velocity of A = 3v
radius of orbit of A = 4R
Let velocity of B =V
radius of orbit of B = R

 \frac{V}{3v}= \sqrt{ \frac{4R}{R} } \\ \\\frac{V}{3v}= \sqrt{4}=2\\ \\V=2 \times 3v\\ \\ V=6v

Speed of satellite B is 6v.
3 5 3
i got the same answer using law of time period , is it correct
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