In a cyclic quadrilateral, Opposite angles are supplementary.
angle A + angle C = 180 deg. and also angle B + angle D = 180 deg.
Now 2x + 4 + 2y + 10 = 180 => x+y = 83 deg.
similarly, y+3+4x-5 = 180 => 4x+y = 182 deg.
solving the two simultaneous equations in x and y we get,
3x = 99 deg; x= 33 deg
y = 50 deg.
now calculate A,B,C and D.
A = 70 deg => C = 110 deg
B = 53 deg => D = 127 deg