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2015-04-12T02:00:14+05:30

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Heat required to melt 1kg of ice at 0⁰C = 330 kJoules/kg * 1kg = 330 kJ

let the mass of watr vapour be = m kg

Heat present in water vapour at 100⁰C
           = latent heat of vapourization + heat due to temperature
         = 2260 kJ/kg * m kg + m kg * 4.18 kJ/kg/°C * 100°C
         = m * [ 2260 + 418 ]  k J

thus m = 330 / 2678  = 0.1232 kg = 123.2 grams



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