1.A chord of a circle is equal to its radius.find the angle subtended by this chord in the major segment
2.ABCD is a quadrilateral in which AB is the largest side and CD is the shortest side.prove that angle is greater than angle A and angle D is greater than angle B



The Brainliest Answer!
1) Chord of the circle is equal to its radius. 

Hence the triangle formed by two radii and the chord is an equilateral triangle. 

The angle subtended at the centre is 60 degrees

Angle subtended by the chord in the major segment is half of the angle at the centre. That means, it measures 30 degrees

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I want the answer of 2nd question
its not possible to post the answer now...please post the question 2 again...i will answer it