2 litres of an ideal gas : V1 = 2 litres
P1 = 10 atms
T = constant
V2 = 10 litres
=> P2 = P1 V1 / V2 = 2 atm
work done =
This is the work done in expansion of the gas. As the gas remains at the same temperature, there is no change in the internal energy.
So energy absorbed is = 3.2607 kJoules.