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40 cattle can feed for 4 days
if there were 10 more cattle, number of cattle = 40+10 = 50
let number of days they can feed = x

(note: since number of days the cattle can feed is inversely proportional to the number of cattle,
no. of cattle × no. of days = constant
⇒ 40×4 = 50×x
⇒ 50x = 160
⇒ x = 160/50 = 3.2 days

His food would last for 3.2 days if he had 10 more cattle.

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