# NaCl reacts with AgNO3 to form AgCl and NaNO3 then a) mass of NaCl = mass of NaNO3 b) mass of AgNO3 = mass of AgCl c) total mass of NaCl and NaNO3 = total mass of AgNO3 and AgCl d) total mass of NaCl and AgNO3 = total mass of AgCl and NaNO3.

2
by parthvaja123

2015-03-10T22:14:57+05:30
NaCl + AgNO3  ----------------->  AgCl + NaNO3
one mole of NaCl and one mole of AgNO3 gives one mole of AgCl and one mole of NaNO3.
weight of one mole of
NaCl = 58.5 and AgNO3 = 170
total weight of reactant = 170+58.5 = 228.5
weight of one mole of
AgCl = 143.5 and NaNO3 = 85
total weight of product = 143.5+85 = 228.5
hence total mass of NaCl and AgNO3 = total mass of AgCl and NaNO3
hence option (d) is correct.

2015-03-11T14:42:02+05:30
ans is option(d)
NaCl + AgNO3 -->  AgCl + NaNO3

NaCl = 58.5 and AgNO3 = 170
total mass  of the reactant = 170+58.5 = 228.5
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AgCl = 143.5 and NaNO3 = 85
total mass of the product = 143.5+85 = 228.5
the total mass of reactants is equal to the total mass of the product after reaction according to law of conservation of mass proposed by A. lavoiser.
hence total mass of NaCl and AgNO3 = total mass of AgCl and NaNO3