# A student recorded the mass of dry raisins as 3.0 g and the mass of raisins after soaking in water is 4.8 g. Find the percentage of water absorbed by raisins during the experiment.

2
by Rohs

## Answers

2015-03-11T18:24:50+05:30

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Mass of dry raisins, = 3.0g
mass of wet raisins, = 4.8g
mass of water absorbed,

% of water absorbed =

60% water was absorbed.
2015-03-11T18:34:27+05:30
Given,

The mass of dry raisins
: 3.0 gram
The mass of water-soaked raisins : 4.8 grams

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Amount of water, the raisins soaked = (4.8-3.0) grams
= 1.8 grams

Amount of water, the raisins soaked in percentage = 1.8/3.0 * 100
= 60.0 % (Ans.)

Answer: Therefore, the raisins soaked 60% of water.