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The hypotenuse of a right angled triangle is 1m more than twice the shortest side.If the third side is 7cm more than the shorter side,find the sides of the triangle.

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by yogamonica

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by yogamonica

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The Brainliest Answer!

third side(bc)=x+7

diagonal(ac)=2x+1

use pythagorian theoram

ac²=ab²+bc²

(2x+1)²=(x+7)²+x²

4x²+1+4x=x²+49+14x+x²

4x²+4x+1=2x²+14x+49

2x²+4x-14x+1-49=0

2x²-10x-48=0

2x²-10x=48

x²-5x=24

x²-5x-24=0

(x-8)(x+3)=0

x=8 or x=-3

use x=8

third side=x+7=7+8=15

diagonal= 2*8+1=17

third side say(bc)=x+7

diagonal say(ac)=2x+1

using pythagoras theorem

ac²=ab²+bc²

(2x+1)²=(x+7)²+x²

4x²+1+4x=x²+49+14x+x²

4x²+4x+1=2x²+14x+49

2x²+4x-14x+1-49=0

2x²-10x-48=0

2x²-10x=48

x²-5x=24

x²-5x-24=0

(x-8)(x+3)=0

x=8 or x=-3

so, x=8

third side=x+7=7+8=15

diagonal= 2*8+1=17