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2015-03-14T19:00:54+05:30

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P= 60 w
time= 30 m
=1/2 hr

electrical energy=
 \frac{pt}{1000  } \\  \\ 
 \frac{60*0.5}{1000} \\  \\ 
 \frac{30}{1000}   =0.03 kwh
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2015-03-14T19:06:07+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Power of tester = 60W = 60J/s
time = 30m = 30×60 s = 1800s

Energy consumed = Pt = 60×1800 = 108000J = 108kJ
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both are correct..0.03 kwh=108 kj