# If the perimeter of a rectangular field is 46 cms. and the area is 120 sq. cms. then find the dimensions of the field that is the length and breadth.

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by sararisa

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by sararisa

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perimeter p = 46 cms = 2(l+b)

area = l×b = 120 cm²

-> (l+b) ^2 = (l+b)^2 - 4lb

-> 23 ^ 2-4 (120 ) = 529 - 480

= 49

so, l - b = 7 cm

and now l+b = 23

-> 2L = 30

30 ÷2

soo 15 is the length

and now coming to breadth

l + b = 23

so now subtract l from 23

L + B = 23

B= 23 - 15

B = 8 cm