Answers

2014-04-21T12:56:48+05:30
v=R( \frac{1}{n_1^2}- \frac{1}{n_2^2}  )
v=1/lambda=1/(16/15R)=15R/16
for lyman n1=1
 \frac{15R}{16}=R( \frac{1}{1^2}- \frac{1}{n^2}  ) \\  1-\frac{15}{16}= \frac{1}{n_2^2}    \\ \frac{1}{n_2^2}  = \frac{1}{16}
n_2^2=16 \\ n_2=4
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