Answers

2015-03-15T21:07:35+05:30
We know that the tangents drawn from an external point to a circle are equal in length
So...
AP=AQ......(1)
BP=BR......(2)
CQ=RC......(3)
Now, the given triangle is an isosceles, So  AB=AC
Subtract AP from both sides, we get
AB-AP = AC-AQ (Using (1) )
BP=CQ
=> BR=CQ  (Using (2) )
=> BR=CR  (Using (3) )
So, BR=CR ( shows that BC is bisected at the point of contact)

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