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## Answers

The Brainliest Answer!

then y-x=z-y

2y=x+z

y=x+z/2

According to question

(x+y-z)(-x+y+z)

x-z+

__x+z__(-x+

__x+z__+z)

2 2

__(2x-2z+x+z)__

__(x+z+2z-2x)__

2 2

1/4 (3x-z)(3z-x)

d=common difference

x+d=y

x+2d=z

x+y=x+x+d

(x+y-z)=x+x+x+d-x+2d=3x+d-x+2d=2x-d

(-x+y+z)=-x+x+d+x+2d=x+3d

so

**(x+y-z) (-x+y+z)=(2x-d) (x+3d)**