Answers

2015-03-20T12:33:13+05:30
Tanα+cotα=2
tanα+1/tanα=2
tan^2α+1=2tanα
tan^2α-2tanα+1=0
tanα=-(-2)+or-√(-2)^2-4.1.1 =2+or-√4-4 =2/2=1
             2(1)                            2
 
tanα=1
sec^2α-tan^2α=1
sec^2α=tan^2α+1 =>(1)^2+1 =1+1=2
secα=√2
therefore,secα=√2

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