# A charge Q is uniformly distributed over a long rod AB of length L .The point is placed left of point A at a distance L.Find electric potential at point O Answer is Q ln(2)/4 pi absolute electric permeability L

1
by kaushikravikant

2015-04-02T07:31:44+05:30

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See diagram.

Potential dV due to a small element dx of the rod AB at a distance x  from A.  The element dx has a charge = dq = Q/L * dx.

The potential (electrostatic) due to dq at point O, which is L distance away from A
=

excuse me pls. In the above answer, the integral answer is not tan^-1 x. It is Ln [ x' + sqroot(1+x'^2) ]. The upper limit is 1 and lower limit is 0. Evaluating this expression with these limits gives: Ln (1 + sqroot(2)).
Hence, the answer is Q/(4πεL) * Ln (1+√2). This is correct.
thankyou very much