Answers

2015-03-21T18:31:56+05:30
3x^2-px+3 Here a=3 b=p c=3 Delta=b^2-4ac =>p^2-4×3×3 =>p^2-36 =>p^2=36 =>p^2=6^2 =>p= plus or minus 6 The value of p is plus or minus6
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2015-03-22T03:35:11+05:30

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3 x² - p x + 3 = 0
Discriminant = p² - 36  must be greater than or equal to 0, for real roots.
   p ≥ 6  or  p ≤ - 6

P belongs to the real value set given by:
            p ∈ (-∞ , -6 ]  U  [6, ∞)

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