In the figue ABCD is a square and EF parallel BD . PROVE BE = DF

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no this answer is complete guyz
miss sadhna it is not given that DB is angular bisector but it is because DC = BC ( side of square ) .
thrfr angle CDB = angle CBD . and this question is class for 9th and this question is came in my SA2 exams .


ABCD is a square ,
=> BC=DC,
also, DB || EF, (given)
=> Distance between lines DB and EF is equal at every point.
Thus, DF=BE,

Hence Proved...
Hope it helps
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