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0.2M acetic acid contains 0.2 moles of acetic acid in 1L solution.
volume of 0.2 moles acetic acid = 11.55 ml
volume of 1 mole of acetic acid =  \frac{11.55}{0.2}= \frac{11.55 \times 10}{2} =57.75ml

1M acetic acid contains 1 mole of acetic acid and its volume is 57.75ml.