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1) water : 18 gm / mole = 6.023 * 10^23 molecules / mole

= 18 ml /mole => 1 ml contains 6.023 * 10^23 / 18 molecules

2) total number of protons in one molecule = atomic numbers = 20+6+8 * 3 = 50

total molecular weight of Calcium carbonate = 100

number of protons = 50 * 6.023 * 10^23 * 10 gm/100 gm

3) 33.6litres of O2 at STP consists of 33.6/22.4 = 1.5 moles = 48 gms

in one molecule of potassium chlorate 3 atoms = 1.5 moles of oxygen.

so we need 1.5 moles of O2 => 1 mole of KCLO3 => 122.5 gms

4) C6 H6 : mass of H : 6 mass of C: 6*12 = 72

% composition of H : 6/(72 + 6) = 7.7% %f of C : 92.3%

5) HCl : 36.5 gm/mole H2 SO4 : 98 gm/mole

there are 2 ions per HCl molecule and 3 ions per molecule of H2SO4.

ions: [ 2 * 9.125 gm/ 36.5 gm/mole * 3 * 73.5 gm / 98 gm/mole ] 6.023 * 10^23 molecules/mole

6) atomic mass = 6.023 * 10^23 * 13.8 gms / [4.6 * 10^22 ] = 180.69

7) 2 NH3 : N2 + 3 H2

1 moles of N2 gives 2 moles of ammmonia.

2.8 gms of N2 = 2.8 / 28 moles = 0.1 moles

so 0.1 moles gives 0.2 moles of ammonia. For this 0.3 moles of H2 are needed. 0.3 moles at NTP occupy 22.4 * 0.3 litres

8)

2 C H I3 + 3 Ag = C2 H2 + 6 Ag I

produces acetylene or ethyne and Silver Iodide precipitate Yellow color.

Acetylene gas produced is = 1/2 * 0.01 mole = 0.005 moles

so its volume at NTP = 22.4 * 0.005 = 0.112 litres = 112 ml

9) 3 Na OH + H3 PO4 => Na3 PO4 + 3 H2 O

9.8 gms of acid => 1/10 moles as its molecular weight is 98

so need 0.3 moles of sodium hydroxide. that is 0.3 * 40 gms

10) 4 Al + 3 O2 ==> 2 Al2 O3

27 grams of Al => 1 mole. so it reacts with 3/4 moles of O2 = 24 grams

11) 2 Ag2 CO3 + O2 => 2 Ag2 O + 2 CO2

276 gms of silver carbonate is 1 mole => we have 0.01 moles.

residue Ag2 O has 232 molecular weight.

so 0.01 moles will give rise to 0.01 moles of silver oxide, which is 2.32 gms

12) Co2 has 44 molecular weight. limestone : Ca CO3 => Ca O + CO2

84 gm of Ca Co3 is one mole that gives 1 mole of CO2 ie., 44 gms

2 gm of calcium carbonate limestone is calcined then we get

44/84 * 2 gms.

= 18 ml /mole => 1 ml contains 6.023 * 10^23 / 18 molecules

2) total number of protons in one molecule = atomic numbers = 20+6+8 * 3 = 50

total molecular weight of Calcium carbonate = 100

number of protons = 50 * 6.023 * 10^23 * 10 gm/100 gm

3) 33.6litres of O2 at STP consists of 33.6/22.4 = 1.5 moles = 48 gms

in one molecule of potassium chlorate 3 atoms = 1.5 moles of oxygen.

so we need 1.5 moles of O2 => 1 mole of KCLO3 => 122.5 gms

4) C6 H6 : mass of H : 6 mass of C: 6*12 = 72

% composition of H : 6/(72 + 6) = 7.7% %f of C : 92.3%

5) HCl : 36.5 gm/mole H2 SO4 : 98 gm/mole

there are 2 ions per HCl molecule and 3 ions per molecule of H2SO4.

ions: [ 2 * 9.125 gm/ 36.5 gm/mole * 3 * 73.5 gm / 98 gm/mole ] 6.023 * 10^23 molecules/mole

6) atomic mass = 6.023 * 10^23 * 13.8 gms / [4.6 * 10^22 ] = 180.69

7) 2 NH3 : N2 + 3 H2

1 moles of N2 gives 2 moles of ammmonia.

2.8 gms of N2 = 2.8 / 28 moles = 0.1 moles

so 0.1 moles gives 0.2 moles of ammonia. For this 0.3 moles of H2 are needed. 0.3 moles at NTP occupy 22.4 * 0.3 litres

8)

2 C H I3 + 3 Ag = C2 H2 + 6 Ag I

produces acetylene or ethyne and Silver Iodide precipitate Yellow color.

Acetylene gas produced is = 1/2 * 0.01 mole = 0.005 moles

so its volume at NTP = 22.4 * 0.005 = 0.112 litres = 112 ml

9) 3 Na OH + H3 PO4 => Na3 PO4 + 3 H2 O

9.8 gms of acid => 1/10 moles as its molecular weight is 98

so need 0.3 moles of sodium hydroxide. that is 0.3 * 40 gms

10) 4 Al + 3 O2 ==> 2 Al2 O3

27 grams of Al => 1 mole. so it reacts with 3/4 moles of O2 = 24 grams

11) 2 Ag2 CO3 + O2 => 2 Ag2 O + 2 CO2

276 gms of silver carbonate is 1 mole => we have 0.01 moles.

residue Ag2 O has 232 molecular weight.

so 0.01 moles will give rise to 0.01 moles of silver oxide, which is 2.32 gms

12) Co2 has 44 molecular weight. limestone : Ca CO3 => Ca O + CO2

84 gm of Ca Co3 is one mole that gives 1 mole of CO2 ie., 44 gms

2 gm of calcium carbonate limestone is calcined then we get

44/84 * 2 gms.