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2015-03-23T21:26:41+05:30

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Let the point of departure be A.  Let the aeroplane towards the North be at N and the aeroplane towards the West be at E after 1 and half hours.
the distance AN = 1000 * 1.5 = 1500 km
the distance AW = 1200 * 1.5 = 1800 km

ANW is a right angle triangle.  NW is the diagonal.
   NW² = AN² + AW² = 1500² + 1800²
   NW = 2, 343.075 km

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2015-03-24T02:01:46+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The two planes are 2,343.07 km apart. See the attachment for calculations.
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