# Find the length of the chord which subtends 90 degrees at the centre of circle with radius 5cm?

2
by nvenkateswarlu

2015-03-23T22:05:06+05:30

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The two radii and the chord will form a right angled triangle.
let the chord be x.
see the diagram. using pythagoras theorem,

x² = 5² + 5²
⇒ x² = 25 + 25
⇒ x² = 50
⇒ x = √50 = 5√2 cm

Length of chord is 5√2 cm.
2015-03-23T23:03:19+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The Chord be AB.  Center be O of the circle.
The radii AO and BO are perpendicular, it is given.   AOB is an isosceles right angle triangle at O.

Hence  according to Pythagoras theorem , we have
AB² = AO² + BO² = 5² + 5² = 50 cm²

Length of the chord = AB = √50 = 5√2 cm