# Find the probability that a leap year contains 53 sundays?

2
by nvenkateswarlu

2015-03-23T22:18:43+05:30

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There are 366 days in a leap year. So there will be 52 complete weeks and 2 days.
The 2 days can be any two consecutive days of the week:
Sample space is:

Sunday and Monday
Monday and Tuesday
Tuesday and Wednesday
Wednesday and Thursday
Thursday and Friday
Friday and Saturday
Saturday and Sunday

There are total 7 possibilities and number of possibility of Sunday is 2.
Probability of 53rd Sunday = 2/7
2015-03-23T22:23:10+05:30

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Leap Year has 366 days, den
weeks= 52
Sundays= 52
and 2 days remaining.

Den, the 2 days can be any of the following like >>>>>>>
⇒ Sunday and Monday
⇒ Monday and Tuesday
⇒ Tuesday and Wednesday
⇒ Wednesday and Thursday
⇒ Thursday and Friday
Friday and Saturday
Saturday and Sunday

Therefore Probablity will be......

⇒n(S) = 7
n(E) = 2
P(E) = n(E) / n(S) = 2 / 7
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