# A sample of gas occupies 100 ml at 27 C and 740 mm pressure. what will be the temp of gas when its volume is changed to 80 ml at 740 mm pressure

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V1/V2 = T1/T2

T2 = V2/V1 ×T1

= 80/100×300k

=240k

T2 = V2/V1 ×T1

= 80/100×300k

=240k

T1 T2

here, P1=740mm V1 = 100ml ⇒ 100/1000 liter ⇒ 0.1 L

T1 = 27 c ⇒ 27 + 273 = 300 K

P2 = 740 mm V2 = 0.08 L T2 = X

put value in eq.

⇒

300 x

⇒ X =

740 × 0.1

⇒ X = 240 K

T2 = 240 K