# Car travelling at 36 km/hr due north turms west in 5 sec and maintains the same speed . Find the average accelaation of car in m/s^2 with direction..

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The Brainliest Answer!

Final velocity = -36 i^ km/hr

Change in velocity vector = vfinal - vinitial

= -36 i^ - 36 j^ = -36(i^ + j^) {So, direction is South-West}

| ΔV vector| = √(36^2 + 36^2)

= √2 * 36 km/hr

= √2 * 36 * 5/18 m/sec

= 10√2 m/sec

Accelaration of the car = | ΔV vector| /Δt = 10√2 / 5 =