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The Brainliest Answer!
2015-03-24T12:24:10+05:30
 Initial velocity = 36 j^ km/hr (as car is travelling 36 km/hr due north)
Final velocity = -36 i^ km/hr
Change in velocity vector = vfinal - vinitial
                                    = -36 i^ - 36 j^ = -36(i^ + j^) {So, direction is South-West}
| ΔV vector| = √(36^2 + 36^2)
                   = √2 * 36 km/hr
                    = √2 * 36 * 5/18 m/sec
                     = 10√2 m/sec
Accelaration of the car = | ΔV vector| /Δt = 10√2 / 5 = 2√2 m/sec (South-west)


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I didn't understand this equation plz help -- | v vector|=√(36^2+36^2) plz explain in short