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If origin is the center of the Rhombus given, then the portion of the line x + 2 y = 4 that is in the first quadrant is one side of Rhombus.

The equation is :  x/4 + y/2 = 1
so x axis intercept is 4 units and y axis intercept is 2 units.
The diagonal of the triangle formed by the x- and y intercepts of the line is the side of rhombus.  It is equal to  √(4²+2²) = 2√5 units

The vertices of the side are :  (0, 2)  and (4, 0)
From symmetry about the origin:  the other two vertices are :  (0, -2) and  (-4, 0)

1 5 1