# A body of mas 1.5kg is thrown vertically upwards with an initial velocity of 15m/s what will be its potential energy at the end of 2sec

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U = 15 m/s

g = 9.8 m/s²

t = 2s

h = ut - 0.5gt²

⇒ h = 15×2 - 0.5×9.8×2²

⇒ h = 30 - 19.6

⇒ h = 10.4m

Potential Energy = mgh = 1.5×9.8×10.4 = 152.88 J

g = 9.8 m/s²

t = 2s

h = ut - 0.5gt²

⇒ h = 15×2 - 0.5×9.8×2²

⇒ h = 30 - 19.6

⇒ h = 10.4m

Potential Energy = mgh = 1.5×9.8×10.4 = 152.88 J

Initial velocity (u) = 15 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time taken (t) = 2s

Height (h) = ?

h = ut - 0.5 gt²

⇒ h = 15×2 - 0.5×9.8×2²

⇒ h = 30 - 19.6

⇒**h = 10.4m**

Potential Energy (PE) = mgh = 1.5×9.8×10.4 = 152.88 J

Acceleration due to gravity (g) = 9.8 m/s²

Time taken (t) = 2s

Height (h) = ?

h = ut - 0.5 gt²

⇒ h = 15×2 - 0.5×9.8×2²

⇒ h = 30 - 19.6

⇒

Potential Energy (PE) = mgh = 1.5×9.8×10.4 = 152.88 J