Answers

2015-03-26T19:50:14+05:30
Consider triangles BEC and CDB
<E=<D
BD=EC  (given)
BC=BC  (common)
hence,triangle (BEC=CDB) by RHS congruence criteria
i.e.<B=<C
so, AC=AB, (sides opposite to equal angles are equal)
thus,it is proved that ABC is an isosceles triangle
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2015-03-26T19:51:13+05:30
In triangles BEC and BDC, 
BC is common
BD = CE (given)
<CEB = <BDC

Thus triangles BEC and BDC are congruent.
or, <ABC = <ACB (cpct)
Therefore, AB = AC (Opposite sides of equal angles are equal)
So, we can say that ABC is isosceles.

Hope that helps !!
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