# ABCD is a parallelogram and X is the mid point of AB.If area of AXCD=24cm sq..Find the area of triangle ABC.

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by skandaSehgal

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by skandaSehgal

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X is the m.p. of AB

ar.AXCD=24cm^2

TO FIND

the ar.ABC

SO,

ar.AXC=1/2 ar.ABC (CX is the median as X is the m.p.)

ar.ABC=ar.ADC (AC is the diagonal and the diagonal divides the //gm into 2 cong.triangles)

Ar.AXCD=1/2 ar.ADC+ADC

AR.AXC=1/3 ADC=8cm^2

hence ar.ABC=8*2=16cm^2