# What is the largest no which when divided with 71 & 126 leaves a remainder 6 & 9 respectively

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by ashvin

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by ashvin

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Dividend=quotient * divisor + remainderÂ

d=q71+6

d=a126+9

71q+6=126a+9

This is a way you can solve

but is 71 the divisor or dividend here?please say

ill solve further

d=q71+6

d=a126+9

71q+6=126a+9

This is a way you can solve

but is 71 the divisor or dividend here?please say

ill solve further

126=ay+9

ax=65,ay=117

65=5x13

117=3x3x13

since both have common factor 13

the largest number which divides is 13

(In otherwords just found hcf)