# A cylindrical jar of cross sectional area of 50cm^2 is filled with water to a height of 20cm. it carries a tight-fitting piston of negligible mass. the pressure at the bottom of the jar when a mass of 1kg is placed on the piston (ignore atmospheric pressure, given:g=9.8)

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## Answers

2015-04-01T17:59:33+05:30

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Force on the bottom of the jar = weight of water column + weight of given mass
= (50 cm² * 20 cm * 1 gram/cm³  + 1 kg) * g
= 2 kg * 9.8 m/sec²
= 19.6 Newtons

Pressure exerted on the bottom surface of the jar
= force/ surface area = 19.6 N/ 50 cm²
= 19.6 N / 0.0050 m²
= 3920 Pa

In reality, the actual pressure will be the atmospheric pressure + the above calculated  pressure.