# Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until total volume is 10 litres. How much heat is absorbed and how much work is done in expansion?

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by brahmaManne585

2015-04-05T20:03:23+05:30

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V1 = 2 Litres      P1 = 10 atm          V2 = 10 litres
T = constant as isothermal expansion.
Since, the temperature is constant, the change in internal energy = 0.

So work done = heat absorbed.

P V = constant = K    => P = K / V
K = P1 V1 = 2 litres * 10 atm = 20 atm-litres

1 atm = 1.01325 * 10⁵  Pa or N/m²
1 litre = 1000 cc = 10⁻³ m³

Work done = heat absorbed = 20 * 1.01325 * 10⁵ * 10⁻³  Joules
= 2, 026.5  Joules  or  2.0265 kilo Joules

forgot to multiply with Ln 5 : Work done= heat absorbed = 3.26 kJoules