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2015-04-05T20:03:23+05:30

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V1 = 2 Litres      P1 = 10 atm          V2 = 10 litres
T = constant as isothermal expansion.
   Since, the temperature is constant, the change in internal energy = 0.

So work done = heat absorbed.

   P V = constant = K    => P = K / V
   K = P1 V1 = 2 litres * 10 atm = 20 atm-litres

W=\int\limits^{V_2}_{V_1} {P} \, dV\\\\=\int\limits^{V_2}_{V_1} {\frac{K}{V}} \, dV\\\\=K[Ln\ V]_{V_1}^{V_2}\\\\=K*Ln\ \frac{V_2}{V_1}\\\\W=20\ Ln\ \frac{10}{2}=20\ Ln\ 5\ atm-litres

 1 atm = 1.01325 * 10⁵  Pa or N/m²  
  1 litre = 1000 cc = 10⁻³ m³

Work done = heat absorbed = 20 * 1.01325 * 10⁵ * 10⁻³  Joules
           = 2, 026.5  Joules  or  2.0265 kilo Joules

1 5 1
forgot to multiply with Ln 5 : Work done= heat absorbed = 3.26 kJoules