Answers

2015-03-31T23:28:23+05:30
If the 3 points are collinear then the area formed by the triangle of the given points shall be 0
A(p,2)    B(-3,4)   C(-7,1)

So, Area of ABC =1/2 [x1 (y2 - y3) + x2(y3 - y1) + x3 (y1 - y2)] = 0

substituting the values,

=> 1/2{p (2) -3 (-1) -7 (-2)} =0

=> 2p +3 +14 =0
=> 2p = -17
=> p =-17/2


0
2015-04-01T06:49:31+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
If 3 points are collinear then Ιx₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)Ι=0
x₁=p,y₁=2,x₂=-3,y₂=4,x₃=-7,y₃=1.
Ιp(4-1)+(-3)(1-2)+(-7)(2-4)Ι=0
Ι3p+3+14Ι=0
3p=-17
p=-17/3

Hope this helps you ............... :)
1 5 1
then why was it reported by someone else why do they do so
i don't understand
i think he reported urs bcoz u missed to keep 1/2 in the formula. but although u keep the result will be same :)
oh may be
yaah :)