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A boat having a length 3 m and breadth 2 m is floating on water the boat sinks by I cm, when a man gets on it .What is the mass of the man ?

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= 0.06 m3.

Mass of man = Volume of water displaced x Density of water

= (0.06 x 1000) kg

= 60 kg.

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We use the Archimedes law.

The additional volume of water displaced by the boat when the man gets onto it,

= 3 m * 2 m * 1 cm = 0.06 m³

So the weight of the man = weight of 0.06 m³ of water

= 0.06 m³ * 1000 kg/m³

= 60 kg

The additional volume of water displaced by the boat when the man gets onto it,

= 3 m * 2 m * 1 cm = 0.06 m³

So the weight of the man = weight of 0.06 m³ of water

= 0.06 m³ * 1000 kg/m³

= 60 kg