# If the nth term of a geometric progression 162, 54, 18,.... and 2/81, 2/27, 2/9 ... are qqual, then find the value of npls answer me as soon as possible..

2
by amina

2015-04-01T13:52:53+05:30

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N=5
for a geometric progression, the nth term is a(r)^n-1. a is the first term. r is the common ratio.
so,
A(R)^n-1 = a(r)^n-1
A=162, R=54/162 for the 1st geometric progression.
a=2/81, r= (2/27)/(2/81) for the 2nd geometric progression.
solve and get the value for n.

hope this helped!
still, if you are having doubt, ask me where u couldn't understand n i will help :)
2015-04-01T15:55:58+05:30

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There are two geometric progressions.
The nth term of both are same.

for 162,54,18...
a = 162, r = 54/162 = 1/3
for 2/81, 2/27, 2/9...
a = 2/81, r = (2/27) / (2/81) = 81/27 = 3