Answers

2014-04-23T22:55:31+05:30
Given,
distance(r)=2m
q1=8*10^-6 C
q2=10*10^-6 C
force between them(F)=?
we know that,by Coulomb's law;
F=k(q1*q2)/(r^2) [where k=9*10^9 Nm^2/C^2 appr.]
F=9*10^9[8*10*10^(-6-6)]/2^2
F=18*10^-2
F=0.18 N
therefore,force between given two charges is 0.18 N

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  • Brainly User
2014-04-23T23:58:40+05:30

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Sub in Coulomb's law 1/4piepsilonnot product of charges /distance square
on further solving 180 *10 power -2
 newton
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