# Two charges q₁ and q₂ are at a distance 2m, where q₁=8μC and q₂=10μC .What is the force between the charges?

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distance(r)=2m

q1=8*10^-6 C

q2=10*10^-6 C

force between them(F)=?

we know that,by Coulomb's law;

F=k(q1*q2)/(r^2) [where k=9*10^9 Nm^2/C^2 appr.]

F=9*10^9[8*10*10^(-6-6)]/2^2

F=18*10^-2

F=0.18 N

therefore,force between given two charges is 0.18 N

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Sub in Coulomb's law 1/4piepsilonnot product of charges /distance square

on further solving 180 *10 power -2

newton

on further solving 180 *10 power -2

newton