# Find the work required to make a soap bubble of radius 0.02m?Surface Tension of soap solution=0.03N/m.

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by prateekthesrk

2015-04-02T08:49:57+05:30

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⇒Radius of the soap bubble= 0.02 m ∛ ⇒Surface tension of the soap solution=0.03N/m ⇒Let us find the surface area. so , ⇒surface area = 4(π) r² .⇒=4×22/7×(0.2 )² ⇒No .of surface area of the soap bubble = 2 ( Outer and inner area ) ⇒Surface area is given as TΔS per surface ⇒Let us next find the total surface area =2 (TΔS) ⇒E = 2 ×0.03 × 4×22/7 × (0.2 )² Joule.....is the ans.
2015-04-02T13:37:24+05:30

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Radius of bubble, r = 0.02m
surface tension, T = 0.03N/m

Work required = surface area×surface tension
surface area = 4πr²
number of surfaces = 2
⇒ S = 2×4×3.14×0.02² = 0.01 m²

Work = 0.01×0.03 = 0.0003 J = 3×10⁻⁴ J