# The question is based on probabilities from tabled data. Please download the attachment to view the question.

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by meheh

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by meheh

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Relative frequency of

A = 0.25

B = 0.35

C = c

D = 0.275

Sum of relative frequencies = 1

⇒ 0.25+0.35+0.275+c = 1

⇒ 0.875 + c = 1

⇒ c = 1 - 0.875

⇒ c = 0.125

frequency of C = 40

let total frequency = x

then 0.125 × x = 40

⇒ 0.125x = 40

⇒ x = 40/0.125 = 320

frequency of A = 0.25×320 = 80

frequency of B = 0.35×320 = 112

frequency of A = 0.275×320 = 88

See the complete table in the attachment.

A = 0.25

B = 0.35

C = c

D = 0.275

Sum of relative frequencies = 1

⇒ 0.25+0.35+0.275+c = 1

⇒ 0.875 + c = 1

⇒ c = 1 - 0.875

⇒ c = 0.125

frequency of C = 40

let total frequency = x

then 0.125 × x = 40

⇒ 0.125x = 40

⇒ x = 40/0.125 = 320

frequency of A = 0.25×320 = 80

frequency of B = 0.35×320 = 112

frequency of A = 0.275×320 = 88

See the complete table in the attachment.