# Divide 4864 into three parts such that the second part is five times the first and the ratio of the second part to the third part is 3:4

2
by pjjaiswal

2015-04-02T23:16:14+05:30

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Second part = 3x Third part = 4x Second part = 5 first part 3x = 5 first part First part = 3x/5 1st part + 2nd part + 3rd part = 4864 3x/5 + 3x + 4x = 4864 3x + 15x + 20x = 4864*5 38x = 24320 X = 640 1st part = 3x/5 = (3*640)/5 = 384 2nd part = 3x = 3*640 = 1920 3rd part = 4x = 4*640 = 2560
2015-04-02T23:19:44+05:30

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We will consider three numbers x,y & z such that there sum is 4864
so,
x+y+z=4864  ..................(i)

ATQ,
y=5x
=> x=y/4
and
y/z=3/4

=>z=4y/3    (cross multiplying)

Substituting the values of x , z in equation 1

=>y/4 + y + 4y/3=4864
(
Taking LCM i.e. 15 )

=> (3y+15y+20y)/15=4864

=>solving the equation gives;

y=1920,

Thus

x= y/5=1920/5=384

z=4y/3=4(1920)/3=2560

Thus three numbers are
384,1920,2560

THATS ALL FOLKS !!!